2x^2-25x+9=0

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Solution for 2x^2-25x+9=0 equation: 



2x^2-25x+9=0

a = 2; b = -25; c = +9;
Δ = b2-4ac
Δ = -252-4·2·9
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{553}}{2*2}=\frac{25-\sqrt{553}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{553}}{2*2}=\frac{25+\sqrt{553}}{4}
$

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